Question 157009
Use the following identity to factor it:
{{{a^3-b^3=(a-b)(a^2+ab+b^2)}}}
{{{54x^3-16y^3}}}
={{{2(27x^3-8y^3)}}}
={{{2((3x)^3-(2y)^3)}}}
={{{2(3x-2y)((3x)^2+(3x)(2y)+(2y)^2)}}}
={{{2(3x-2y)(9x^2+6xy+4y^2)}}}