Question 156977
{{{16z^5+12z^4-10z^3}}}
you start by factoring out a common term to all which winds up being {{{z^3}}}
the formula becomes {{{(z^3)*(16z^2+12z-10)}}}.
{{{16z^2+12z-10}}} is a quadratic equation that can be factored by sight (with a little fiddling around cause it wasn't that easy) so the completed factorization becomes {{{(z^3)*(2z-1)*(8z+10)}}}.