Question 156965
{{{(2x+5)/(x^2+8x+15)-(x+2)/(x^2+8x+15)=(2x+5-(x+2))/(x^2+8x+15)=(2x+5-x-2)/(x^2+8x+15)=(x+3)/(x^2+8x+15)=(x+3)/((x+5)(x+3))=cross((x+3))/((x+5)cross((x+3)))=1/(x+5)}}}



So {{{(2x+5)/(x^2+8x+15)-(x+2)/(x^2+8x+15)=1/(x+5)}}} where {{{x<>-5}}} or {{{x<>-3}}}