Question 156935
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Edwin's solution:
My solution takes it all the way to fractional 
exponents with no parentheses, which is what
I think you are looking for:
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Could someone please show me how to solve this equation? This is not coming up the way i need it to but the 7 is supposed to like a cubed square root. I am supposed to rewrite with rational exponents. 
{{{((7)sqrt (3x^2y))^11}}}
<pre><font size = 4 color ="indigo"><b>
I assume you mean this:

{{{(root(7,3x^2y))^11}}}

which you make on this site by putting this

 {{(root(7,3x^2y))^11}}

within triple braces, not double braces like above. 

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Anyway, on this:

{{{(root(7,3x^2y))^11}}},

we use this rule:

{{{(root(INDEX,RADICAND))^EXPONENT=RADICAND^((EXPONENT)/(INDEX)))}}}

{{{(root(7,3x^2y))^11=(3x^2y)^(11/7)=(3^1x^2y^1)^(11/7)=3^(1*11/7)x^(2*11/7)y^(1*11/7)=3^(11/7)x^(22/7)y^(11/7)}}}

Edwin</pre>