Question 156924
i believe this meets your requirements.
check it out and let me know what you think.
i used the slope intercept formula to get the equation.
the formula is:  y = mx + b where m is the slope and b is the y-intercept.
i started with {{{y = -4x}}} since -4 is the slope of the line you wanted this line to be parallel to.
getting the y intercept was a little tricky but here's how i did it.
i plotted for x points from -5 to + 5.
i then started with x = -3 to fix the line to pass through where you wanted it to.  i set the y value at 2 at that point (line goes through (-3,2).
with a slope of -4 there is a drop of 4 units in the y value for every increase of 1 unit in the x value.  conversely there is an increase of 4 units in the y value for every decrease of 1 unit in the x value.
the plot poiints look like the following:
start of plot points........
x,y
-5,10
-4,6
-3,2
-2,-2
-1,-6
0,-10
1,-14
2,-18
3,-22
4,-26
5,-20
end of plot points.............
looking at this table i saw that the y-intercept (y value when x is 0) is -10.
the equation then becomes {{{y=-4x-10}}}
the graph looks like the following:
{{{graph(400,1200,-5,5,-20,10,-4x-10)}}}
an algebraic way to find the b value in the equation would be as follows:
starting with {{{y = -4x}}}, i would solve the equation for {{{x = -3}}}.
{{{y = -4 * -3}}} yields {{{y = 12}}}.
the answer i want is 2 so i would need to subtract 10 from it.
that becomes my b value, so the equation then becomes {{{y = -4x-10}}} which is the same result without looking at plot points.