Question 156890
{{{ 2/(x^2+2x-8) + 2/(x^2-6x+8) }}}
now, if you factor each denominator:
{{{ 2/((x+4)(x-2)) + 2/((x-4)(x-2)) }}}
Convert each term to the common denominator of:(x+4)(x-4)(x-2)
{{{ 2(x-4)/((x+4)(x-4)(x-2)) + 2(x+4)/((x+4)(x-4)(x-2)) }}}
{{{ (2(x-4) + 2(x+4))/((x+4)(x-4)(x-2)) }}}
{{{ (2x-8 + 2x+8)/((x+4)(x-4)(x-2)) }}}
{{{ (4x)/((x+4)(x-4)(x-2)) }}}