Question 156875
To find the altitude, A, when after two seconds (t=2), substitute t = 2 into the given equation and solve for the altitude, A.
{{{A(t) = -16t^2+32t+6}}} Substitute t =2.
{{{A(2) = -16(2)^2+32(2)+6}}}
{{{A(2) -64+64+6}}} Simplify.
{{{A(2) = 6}}}
The altitude at 2 seconds is 6 feet, so the ball is on the way down and, at 2 seconds, it is at the same altitude as when it was initially tossed.