Question 156851
{{{(k^4k^(-5))/(k^(-2))^2=(k^4(1/k^5))/(1/k^2)^2=((k^4)/(k^5))/(1/k^2)^2=(1/k)/(1/k^2)^2=(1/k)/(1/k^4)=(1/k)(k^4/1)=k^4/k=k^3}}}



So {{{(k^4k^(-5))/(k^(-2))^2=k^3}}} where {{{k<>0}}}