Question 156745
Solve for x and y"
1) {{{2x-2y = 15}}}
2) {{{4x+4y = 10}}} First, multiply equation 1) by 2 to get:
1a) {{{4x-4y = 30}}} now add this to equation 2) to eliminate the y's
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{{{8x = 40}}} Divide both sides by 8.
{{{x = 40/8}}}
{{{x = 5}}} Now substitute this value of x into either equation 1) or eqation 2) to find y. Let's use equation 1)
1) {{{2x-2y = 15}}} Substitute x = 5.
{{{2(5)-2y = 15}}} Simplify.
{{{10-2y = 15}}} Subtract 10 from both sides.
{{{-2y = 5}}} Divide both sides by -2.
{{{y = -5/2}}}
The solution is: (5, -5/2)