Question 21604
Y>3X+4...PLOT Y=3X+4 AS USUAL BY GIVING DIFFERENT VALUES TO X AND FINDING Y AS TABULATED BELOW
X.......0........1........2...........-1...........-2
Y.......4........7........10...........1...........-2
THE GRAPH WILL LOOK LIKE THIS
{{{ graph( 300, 300, -10, 10, -30, 40, 3*x+4) }}}
YOU GET A STRAIGHTLINE.....ON THIS LINE ANY POINT WILL SATISFY THE GIVEN EQUATION .NOW WE FIND THAT ORIGIN IS ON ONE SIDE OF THE LINE.LET US TEST THE ORIGIN IN THE ABOVE EQN.WE FIND THAT
Y=0 AND 3X+4=3*0+4=4...SO Y<3X+4...HENCE THE REGION FROM THE LINE TOWARDS OR IN THE DIRECTION TOWARDS ORIGIN  IS FOR Y<3X+4.BUT WE WANT THE REGION WHERE Y>3X+4....OBVIOUSLY ,IT IS THE REGION FROM THE LINE SPREADING TO THE OTHERSIDE OR POINTING AWAY FROM THE ORIGIN .