Question 156692
{{{4x^2-1=0}}} Start with the given equation


{{{(2x+1)(2x-1)=0}}} Factor the left side (note: if you need help with factoring, check out this <a href=http://www.algebra.com/algebra/homework/playground/change-this-name4450.solver>solver</a>)




Now set each factor equal to zero:

{{{2x+1=0}}} or  {{{2x-1=0}}} 


{{{x=-1/2}}} or  {{{x=1/2}}}    Now solve for x in each case



So the answer is 


 {{{x=-1/2}}} (with a multiplicity of 2)