Question 156682
a=2 b=3 c=?


Pythagorean Theorem:
{{{a^2+b^2=c^2}}}


{{{2^2+3^2=c^2}}}
{{{4+9=c^2}}}
{{{13=c^2}}}
{{{sqrt(13)=c}}}


Functions:
sin=b/c
cos=a/c
tan=b/a


cse=c/b
sec=c/a
cot=a/b
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I hope this helped!
-Alani