Question 156674
x-y=-3


First, you want to isolate y to get this thing in y=mx+b form.


x-y=-3


Subtract x from each side
-y=-x-3


Divide both sides by -1
y=x+3


Now you have your equation for the line in y=mx+b form.  m=slope, and b=y-intercept.  Therefore, your slope here is 1 (since x is the same as 1x), and your y-intercept is 3.


Now to graph it, there are many different ways.  I'll show you two ways to do it:


1) Take the equation y=x+3 and plug in a value for x. Any value.  Say 3.
y=3+3
y=6


So one point to plot is (3,6).


Now plug in another random number, like 2.
y=2+3
y=5


(2,5)


Now how about -1?
y=-1+3
y=2


(-1,2)


And one point you already know is (0,3) because of the y intercept.


Now plot the points and draw a line through all four of them:


*[invoke describe_linear_equation 1, -1, -3]


Now the next way I'm going to show you, in my opinion, is an over-complicated brain fart.  But I will show it to you anyway, just in case it will be easier for you to do it this way (maybe).


2)Look at the equation y=x+3.
Your slope=the change in y/change in x.  In other words, in this case, 1/1.  Your y-intercept is 3.


Start at the point (0,3).
Since the change in y is 1, move up one.
Since the change in x is 1, move to the right one.


(Does this feel like a board game yet?)


Now plot the point.  


Repeat the process.


Now go back to (0,3).  Since your slope can also be considered -1/-1, your change in y can be -1.  So move down one.


Same applies to your change in x.  It can be -1.  So move to the left 1.


Plot the point.


Repeat the process.


Draw a line through the points. (Now we're doing a Connect-the-dots)


*[invoke describe_linear_equation 1, -1, -3]


I hope this helped you!
-Alani