Question 22121
f(3) = 3*3^2+2*3= 27+6 =33
g(3) = 3-5 = -2

(f*g)(3) = f(3)*g(3) = 33*(-2) = -66


f(5) = 3*5^2 + 2*5 =75+10=85
g(5) = 5-5 =0
(f-g)(5) = f(5) - g(5) = 85-0=85


(f o g)(x)  
= f[g(x)] 
= 3(x-5)^2 +2(x-5)
= 3(x^2 -10x+25) + 2x -10
= 3x^2 -30x + 75 + 2x - 10
= 3x^2 -28x + 65


R^2 at SCC