Question 23104
m= {{{-3/5}}} passing through (10,4).  In this point x=10 and y=4.


Substitute all three of the above numbers into this formula, and solve for b:

y=mx + b
{{{4=(-3/5)*10 + b}}}
{{{4=-6+b}}}
{{{10=b}}}


So, the equation of the line is 
{{{y=mx+b}}}
{{{y=(-3/5)x + 10}}}


R^2 at SCC