Question 156507
 moving van - rate: 35 mi/hr    time: t hr   distance traveled: 35t mi
 car -        rate: 50 mi/hr    time: (t - .75) hr  dist traveled: 50*(t - .75)mi
When they meet, the distance each has travelled will be the same
{{{d = 35t}}}
{{{d = 50*(t - .75)}}}
{{{35t = 50*(t - .75)}}}
{{{35t = 50t - 37.5}}}
{{{15t = 37.5}}}
{{{t = 2.5}}}hr (note: this is the time expired from when
the van left until it meets the car)
{{{t - .75 = 1.75}}}hr This is the time expired from when the car left 
until it meets the van
So, the car will catch up with the van in 1 hr and 45 minutes
check:
{{{d = 35t}}}
{{{d = 35*2.5}}}
{{{d = 87.5}}}mi
and
{{{d = 50*(t - .75)}}}
{{{d = 50*1.75}}}
{{{d = 87.5}}}mi
OK