Question 156593
Remember you <b>CANNOT</b> divide by zero (ie something like {{{2/0}}} is <b>NOT</b> possible). So this means that if there are values of "p" that make the denominator {{{p^2-49}}} equal to zero, then these "p" values make the expression undefined.



{{{p^2-49=0}}} Set the denominator equal to zero



{{{(p-7)(p+7)=0}}} Factor the left side



{{{p-7=0}}} or {{{p+7=0}}} Set each factor equal to zero



{{{p=7}}} or {{{p=-7}}} Solve for "p" for each case



So if {{{p=7}}} or {{{p=-7}}}, then the denominator is zero. So either {{{p=7}}} or {{{p=-7}}} will make the expression {{{(p^3-4p)/(p^2-49)}}} will make the expression undefined.



note: the numerator plays no part in determining undefined values since 0 in the numerator is possible.