Question 156531
Let x and y the length of the two pieces (x the length of the square and y the length of the circle)
then {{{x+y=350}}} (is the easy equation)

Now we have to find the areas

side of the square is {{{x/4}}} then area of the square is {{{x^2/16}}}

in a circle  {{{2r(pi)=p}}} where r is the radius and p = perimeter
then  {{{r=p/(2(pi))}}}

so {{{r=y/(2(pi))}}}

area of the circle is 
{{{r^2(pi)}}}={{{(y^2/(4(pi)^2))(pi)}}}={{{y^2/(4(pi))}}}  

then the system to solve is:

{{{x+y=350}}} 
{{{x^2/16}}}={{{y^2/(4(pi))}}}