Question 156543
{{{sqrt(x+2)-x=0}}}
then
{{{sqrt(x+2)=x}}}
then
{{{x+2=x^2}}}
then
{{{x^2-x-2=0}}}
then
{{{x = (1 +- sqrt( 1^2-4*1*(-2) ))/(2) }}} =
{{{x = (1 +- 3 )/2 }}} 
then {{{x=-1}}} or {{{x=2}}}
-1 is not a solution of the first eq because {{{sqrt(-1+2)-(-1)=2}}}
2 is a solution of the first eq because {{{sqrt(2+2)-(2)=0}}}

Answer: {{{x=2}}}