Question 22427
So you want to solve the system;

{{{ 2x-y = 7 }}}
{{{ 3x + 2y = 0 }}}


I'll show you an easy way called the substitution method....

In the first equation, solve for y.

{{{ y = -7 + 2x }}}

Now, plug that into the second equation (now that you know what y equals);

{{{ 3x + 2(-7 + 2x) = 0 }}}

Solve that equation for x;

{{{ 3x - 14 + 4x = 0 }}}
{{{ 7x - 14 = 0 }}}
{{{ 7x = 14 }}}
{{{ x = 2 }}}

Now, plug that x back into the first, equation that we solved for y in. {{{ y = -7 + 2x }}}

{{{ y = -7 + 2(2) }}}
{{{ y = -7 + 4 }}}
{{{ y = -3 }}}

So the solution to the system is;

(x,y) = (2,-3)

*** that is where the two lines intersect.