Question 156459
please help me 
[y^2 /(y-4)] - [4/(y-4)]
Since the denominators are the same, combine the numerators to get:
(y^2-4)/(y-4)
You could factor the numerator but the fractio will no reduce.
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[(y^3-5y)/6y] - [(y^3+y+3)/6y] 

Since the denominators are the same, combine the numerators to get:
[y^3-5y-y^3-y-3]/6y

= [-6y-3]/6y

= [-3(2y+1)]/6y

= -[2y+1]/2y
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Cheers,
Stan H.