Question 156401
{{{(y^2-y-12)/(y^2-9)}}}
={{{((y-4)(y+3))/((y-3)(y+3))}}}
={{{((y-4)cross((y+3)))/((y-3)cross((y+3)))}}}
={{{(y-4)/(y-3)}}}
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{{{(3x^2-6x-72)/(2x^2-8x-64)}}}
={{{(3(x^2-2x-24))/(2(x^2-4x-32))}}}
={{{(3(x+4)(x-6))/(2(x-8)(x+4))}}}
={{{(3cross((x+4))(x-6))/(2(x-8)cross((x+4)))}}}
={{{(3(x-6))/(2(x-8))}}}