Question 156371
factor the following expressions completely {{{24x^3-81}}}
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=3(8x^3 - 27)
=3*(2x-3)*(4x^2+6x+9)
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{{{(3a-c)^3-c^3}}}
= [(3a-c) -c]*[(3a-c)^2 + (3a-c)*c + c^2]
= [3a-2c]*[9a^2-6ac+c^2 + 3ac-c^2 + c^2]
= [3a-2c]*[9a^2 - 3ac + c^2]
That's it unless you factor the trinomial using imaginaries.
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solve the equation for x{{{z=x/k-m/k }}}
z = (x-m)/k
zk = x-m
x = m+kz