Question 156335
{{{abx^2-(a^2+b^2)x+ab=0}}}then

{{{x = ((a^2+b^2) +- sqrt( (a^2+b^2)^2-4*ab*ab ))/(2*ab) }}}=
{{{x = ((a^2+b^2) +- sqrt( (a^4+2a^2b^2+b^4)^2-4*a^2b^2 ))/(2*ab) }}}=
{{{x = ((a^2+b^2) +- sqrt( a^4-2a^2b^2+b^4))/(2*ab)}}}=
{{{x = ((a^2+b^2) +- (a^2-b^2))/(2*ab) }}}

then roots are: {{{ 2a^2/2ab =a/b}}} and {{{ 2b^2/2ab =b/a}}}

Solution: {{{x=a/b }}}and {{{x=b/a}}}