Question 156341
{{{18xy^3 + 3xy^2 - 10xy=xy(18y^2+3y-10)}}}

18y^2+3y-10=0
then
{{{y = (-3 +- sqrt( 3^2-4*18*(-10) ))/(2*18) }}} =
{{{y = (-3 +- sqrt( 3^2-4*18*(-10) ))/(2*18) }}} =
{{{y = (-3 +- 27)/(36) }}}
so roots are -30/36 and 24/36
then roots are  -5/6 and 2/3

so  {{{18xy^3 + 3xy^2 - 10xy = xy(x+5/6)(x-2/3)}}}