Question 156138
{{{(3a+2b)/2b= 7c/(n-t)}}} Start with the given equation


{{{(n-t)((3a+2b)/2b)= 7c}}} Multiply both sides by {{{n-t}}}



{{{(n-t)(3a+2b)= (7c)(2b)}}} Multiply both sides by {{{2b}}}



{{{(n-t)(3a+2b)= 14bc}}} Multiply



{{{n-t= (14bc)/(3a+2b)}}} Divide both sides by {{{3a+2b}}}



{{{-t= (14bc)/(3a+2b)-n}}} Subtract "n" from both sides



{{{t=-(14bc)/(3a+2b)+n}}} Multiply every term by -1 to make "t" positive.




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Answer:


So the solution is {{{t=-(14bc)/(3a+2b)+n}}}