Question 23061
I went for the formula: 
{{{(-b +- sqrt(b^2 -(4*a*c)))/(2*a)}}}
a = 1
b = 8
c = 6 
because the equation is in the form av^2 + bv + c = 0
{{{(-8 +- sqrt(64 - 4*6))/2}}}
{{{(-8 +- sqrt(40))/2}}} 
{{{-4 +- sqrt 10}}}
so the answers are:
 -4 +sqrt 10 and 
 -4 -sqrt 10
if you plug these back into the original equation you
will check that you have correctly solved.