Question 155985
Solve for t:
{{{h = 16t^2+vt+s}}}
Since this is a quadratic equation in t, you can use the quadratic formula:{{{x = (-b+-sqrt(b^2-4ac))/2a}}} but change the independent variable from x to t.
Here, a = 16, b = v, and c = s, so we have:
{{{t = (-v+-sqrt(v^2-4(16)(s)))/2(16)}}} Simplifying, we get:
{{{t = (-v+-sqrt(v^2-64s))/32}}}