Question 22489
Your first step is correct:
-2x+5y-6=-11
6+-2x+5y-6=-11+6
-2x + 5y = -5


However, the next step is incorrect.  You need to "UNDO" the -2x by adding +2x to both sides of the equation.  It should look like this:
2x -2x +5y = 2x - 5
5y = 2x -5


Next, you must "UNDO" the 5 that was multiplied by the y.  In order to "UNDO" multiplication, you must DIVIDE both sides by 5.  There are two ways to write this:

{{{(5y)/5 = (2x-5)/5}}}
{{{y= (2x-5)/5}}}


OR YOU CAN WRITE:
{{{ (5y)/5 = (2x)/5 -5/5}}}
{{{ y = (2/5)x -1}}}


Both answers are correct.


R^2 at SCC