Question 155909
 i have to write an equation for the line containing the indicated points.
(0,0) (3,30)
please help by showing me how to do this!!!!
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Put it in the y-intercept form to start, y = mx + b where m is the slope and b is value of x when it crosses the Y-axis (or where 30-0= 0).
First, find the slope m.
m = (y2-y1)/(x2-x1)
m = (30-0)/(3-0)
m = 10
Then use the y = mx + b
y - y1 = m*(x - x1)
y -0 = 10*(x - 0)
y = 10x
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You can use the other point to get the same answer:
y - 30 = 10*(x-3)
y - 30 = 10x -30
y = 10x
That's all.