Question 155683
2(x+1)^2+7(x+1)+3
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It's a quadratic with variable x+1.
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Let x+1 = w and substitute to get:
2w^2 + 7w + 3
Factor:
2w^2 + 6w +w + 3

2w(w + 3) + w + 3
(w+3)(2w+1)
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Substitute back to x's:
(x+1+3)(2(x+1)+1)

= (x+4)(2x+3)
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Cheers,
Stan H.