Question 155497
(Square root of 2X+3) = (square root of X+2) + 2 

X-3=(4 Square root of X+2) GOOD SO FAR.
NOW SQUARE BOTH SIDES AGAIN.
X^2-6X+9=16(X+2)
X^2-6X+9=16X+32
X^2-6X-16X+9-32=0
X^2-22X-23=0
(X-23)(X+1)=0
X-23=0
X=23 ANSWER.
X+1=0
X=-1 ANSWER.
PROOF:
SQRT(2*23+3)=SQRT(23+2)+2
SQRT(46+3)=SQRT(25)+2
SQRT49=5+2
7=7