Question 155540
(8y^2)+(5y)=(2y^2)+(4)
8y^2+5y=2y^2+4
8y^2-2y^2+5y-4=0
6y^2+5y-4=0
(2y-1)(3y+4)=0
2y-1=0
2y=1
y=1/2 or .5 Answer.
3y+4=0
3y=-4
y=-4/3 or -1.333 Answer.