Question 155544
you're using the right technique, but your LCD has too many z's - one is enough


LCD is (z) times (2), (already have the z), times (5), times (z+1)


(10(z+1))-(5(z+1))-(2(z+1))=10(10z) __ 10z+10-5z-5-2z-2=100z __ 3z+3=100z __ 3=97z __ 3/97=z