Question 155488
Soybean=240 lb

Coenmeal=80 lb

Let x=amount of 16% protein needed
Then 320-x=amount of 8% protein needed

Now we know that the amount of pure protein in the 16% mixture (0.16x) plus the amount of pure protein in the 8% mixture (0.08(320-x)) has to equal the amount of pure protein in the final mixture (0.14*320).  So our equation to solve is:
0.16x+ 0.08(320-x)=0.14*320  get rid of parens and simplify

0.16x+25.6-0.08x=44.8  subtract 25.6 from each side

0.16x+25.6-25.6-0.08x=44.8-25.6 collect like terms

0.08x=19.2

divide each side by 0.08
x=240 lb-----------------------amount of 16% mixture needed(soybean)

320-x=320-240=80 lb-------------amount of 8% mixture needed(cornmeal)

CK

240*0.16+80*0.08=320*0.14
38.4+6.4=44.8

44.8=44.8

Hope this helps---ptaylor