Question 155507


{{{2x^2+x-10=0}}} Start with the given equation



{{{(2x+5)(x-2)=0}}} Factor the left side (note: if you need help with factoring, check out this <a href=http://www.algebra.com/algebra/homework/playground/change-this-name4450.solver>solver</a>)




Now set each factor equal to zero:


{{{2x+5=0}}} or  {{{x-2=0}}} 



{{{x=-5/2}}} or  {{{x=2}}}    Now solve for x in each case



So the answers are 



 {{{x=-5/2}}} or  {{{x=2}}}