Question 155473
{{{f(x)=3^x+7}}}

x=-2 then {{{f(-2)=3^-2+7=(1/9)+7}}}
x=-1 then {{{f(-1)=3^-1+7=(1/3)+7}}}
x=0 then {{{f(0)=1+7=8}}}
x=1 then {{{f(1)=3+7=10}}}
x=2 then {{{f(2)=3^2+7=16}}}