Question 155456
Let x and y the numbers
sum is 70 then x+y=70
one is 4 times as large as the other
then x=4y
sytem to solve is

{{{x+y=70}}}
{{{x=4y}}}

using substitution method

{{{4y+y=70}}}
then
{{{5y=70}}}
then
{{{y=14}}}

{{{x+14=70}}}
then
{{{x=70-14=56}}}
Answer: numbers are 14 and 56