<PRE><B>Question 155421</B>
&amp;#8730;(16a^4 b^6 )/&amp;#8730;(128a^6 b^6 ) 

cancel the 16 with the 128 to get 1/8
cancel the a^4 with the a^6 to get 1/a^2
cancel the b^6 with b^6 to get 1/1
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Result:

= sqrt[1/8a^2]

= (1/2a)sqrt[1/2]

= (1/2a)sqrt(2/4)

= (1/4a)sqrt(2)

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Cheers,
Stan H.











 
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