Question 155298
if the path of a frog's jump is approximated by the equation y= -0.25x^2+5x, what is the height of the frog's jump
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The maximum height occurs when x = -b/2a = -5/(2*-0.25) = 5/1/2 = 10
f(10) = -0.25(10^2) + 5(10)

f(10) = -0.25*100 + 50

f(10) = 25 ft.
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The maximum height is 25 ft.
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Cheers,
Stan H.