Question 155294
The sum of two integers is thirty. 
x + y = 30
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Eight times the smaller integer is six more than five times the larger integer.
8x = 5y +6
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Arrange for elimination:
8x + 8y = 240
8x - 5y = 6
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Find the integers.
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Subtract the 2nd equation from the 1st to get:
13y = 234
y = 18 (larger integer)
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Substitute into x + y = 30 to solve for "x":
x + 18 = 30
x = 12 (smaller integer)
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Cheers,
Stan H.