Question 155256
Express in lowest terms:
Factor the numerators and the denominators:
1) {{{(y^2-y-12)/(y^2-9) = cross((y+3))(y-4)/cross((y+3))(y-3)}}} Cancel as indicated to get:
{{{(y-4)/(y-3)}}}
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2) {{{(3x^2-6x-72)/(2x^2-8x-64) = 3(x^2-2x-24)/2(x^2-4x-32)}}}={{{3*cross((x+4))(x-6)/2cross((x+4))(x-8) = 3(x-6)/2(x-8)}}}
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3) {{{((u^2+16u+63)/(u+7))*(1/(u+9)) = (u^2+16u+63)/(u+7)(u+9)}}}={{{cross((u+7))cross((u+9))/cross((u+7))cross((u+9)) = 1}}}