Question 155111
I believe your equation is:
{{{ (3/4)x + 2y = -3 }}}
.
Start by manipulating the equation to make it look like the "slope-intercept" form of a line:
y = mx + b
where
m is the slope
b is the y-intercept at (0,b)
.
{{{ (3/4)x + 2y = -3 }}}
Start by multiplying both sides by 4:
{{{ 3x + 8y = -12 }}}
Now, subtract 3x from both sides:
{{{ 8y = -3x - 12 }}}
Finally, divide both sides by 8:
{{{ y = (-3/8)x - (12/8) }}}
{{{ y = (-3/8)x - (3/2) }}}
.
From the above, we now have:
m (slope) = -3/8
b (y-intercept) = -3/2