Question 155041
The volume of a regular pyramid is found by:
{{{V = (1/3)Bh}}} where: B = area of the base and h = the height of the pyramid.
In this problem, {{{B = sqrt(S(S-a)(S-b)(S-c))}}} using Heron's formuls for the area of a triangle when the three sides are known. S = Semi-perimeter = 30/2 = 15,
a = b = c = 10, so...
{{{B = sqrt(15(125))}}}
{{{B = sqrt(1875)}}}
{{{B = 43.3}}}
So the volume of the pyramid is:
{{{V = 43.3(6)/3}}}
{{{V = 86.6}}}Cubic feet.