<PRE><B>Question 154901</B>
Find four consecutive even integers so that the sum of the first three is 2 more than twice the fourth.
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1st: 2x
2nd: 2x + 2
3rd: 2x + 4
4th: 2x + 6
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EQUATION:
2x + 2x+2 + 2x+6  = 2(2x+6) + 2
6x + 8 = 4x + 14
2x = 6
x = 3
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1st: 2x = 6
2nd: 2x+2 = 8
3rd: 2x+4 = 10
4th: 2x+6 = 12
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Cheers,
Stan H.</PRE>