Question 154765
A picture that was supposedly painted by Vermeer (1632-1675) contains 99.5% of it's carbon=14. The half life for carbon=14 is 5730 years. Is the picture a fake? 
I know the formula to use is(first, Q_0 = Q-naught) Q=Q_0e^-k5730. And I know Q should equal 1/2, but I can't seem to put it all together
-----------------------------
Q(t) = Q(o)(1/2)^(t/5730)
0.995Q(0) = Q(o)(1/2)^(t/5730)
0.995 = (1/2)^(t/5730)
ln 0.995 = (t/5730)ln(1/2)
t/5730 = ln 0.995 / ln(1/2)
t/5730 = 0.007232
t = 41.44 years
The picture is a fake.
===================
Cheers,
Stan H.