Question 154779
a=3b-1
b=2a+2
-------
Since eqn 1 already shows a as a function of b, substitute for a in eqn 2.
b=2*(3b-1)+2
b=6b-2+2
b = 6b
b = 0 (the only possibility)
------------
Sub b into eqn 1
a = 3*0-1
a = -1