Question 154730
{{{ 2 sqrt (x^2+3)= sqrt (-16x-3) }}}
Square both sides
4*(x^2 + 3) = -16x - 3
4x^2 + 12 = -16x - 3
4x^2 + 16x + 15 = 0
*[invoke solve_quadratic_equation 4,16,15]