Question 23014
{{{log(9,5) + log(9,(n+1)) = log(9,6n)}}}


{{{log(b,M) + log(b,N) = log(b,MN)}}}, so {{{log(9,5) + log(9,(n+1)) = log(9,5(n+1))}}}


{{{log(9, 5(n+1)) = log(9,6n)}}}


If {{{log(b, M) = log(b, N)}}}, then {{{M=N}}}


5(n+1) = 6n
5n+5 = 6n


Subtract 5n from each side:
5= n
Remember to check the value of n to make sure you don't have a log of a negative number.  You do not, so the answer n=5 is acceptable.


R^2 at SCC