Question 154464
That would be true.
Take for example y = x^3
When x is very negative y is verty negative.
But when x is very positive y is very positive.
If the function is continuous the y values must
have passed through zero; that means the yvalues
must have intersected the x-axis where y is zero.
And that intersection would be a Real Number zero
for the function.
I said this about a cubic equation; the same would
be true of any odd-powered function.
Cheers,
Stan H.